The bundle app vanished, so we built bundling into the store
Steadyrack sold bundles, a rack and its accessories at a deal price, through a paid bundle app. Then the app’s developer withdrew it from the App Store, and the bundles came off the site. That is the risk nobody prices in when they reach for an app: a monthly subscription is not just a cost, it is a dependency that someone else can end without asking you.
What we did
Rather than move the bundles onto the next subscription, we built the capability into the store as a Shopify Function, native code the client owns outright. A bundle is now a real product. It adds to the cart as one line, and at checkout it expands into its component products so fulfilment sees exactly what to pick. The bundle’s deal price is distributed across those components, so what the customer is charged is always the deal price, never the sum of the parts. The cart drawer and checkout show one bundle line with its contents nested underneath, and Shopify does that rendering natively, with no theme surgery.
We proved the whole thing on a dev store before it went anywhere near the real one: expansion, pricing, quantities, mixed carts with the same product both inside and outside a bundle, and what happens if someone tampers with a selection. Then it was activated on the US store and verified with a live cart, sitting comfortably alongside the store’s other cart apps. This is also the second store we have moved off a rented bundle app onto an owned function, so the pattern is now well worn.
What to take from it
Apps are the right answer for plenty of things, but the closer a capability sits to how you actually sell, the stronger the case for owning it. An owned function has no monthly fee, no third party’s roadmap, and no possibility of disappearing from an app store overnight. If your bundles, your pricing logic or your checkout behaviour live inside someone else’s subscription, it is worth asking what the plan is on the day that subscription stops existing. This client now has a good answer.